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An object with an initial velocity of 4 m//s moves along a straight axis under constant acceleration. Three seconds later, its velocity is 14 m//s. How far did it travel during this time ? |
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Answer» Solution :We're given `v_(0), t and v` and we're asked for `Delta s`. So a is MISSING : it isn't given and it isn't asked for, so we USE BIG Five #1. `Delta s= overline(v)t=(1)/(2)(v_(0)+v) t=(1)/(2) (4 m//s +14 m//s)(3 s)=27 m` |
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