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An object with mass 5 kg is acted upon by a force, vecF = (-3hati + 4hatj) N. If its initial velocity at t = 0 isvecv = (6hati – 12hatj) m s^(-1), the time at which it will just have a velocity along y-axis is

Answer»

2s
5s
15s
10s

Solution :`U_x = 6 ,V_x=0 a_x = (-3)/(5)m//s^2`
` v_x =U_x +a_x t0=6+(-3)/( 5)timplies t=10s`


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