1.

An observer is moving with half the speed of light towards a stationary microwave source emitting waves at frequency 10 GHz. What is the frequency of the microwave measured by the observer ? (Speed of light =3xx10^(8)ms^(-1))

Answer»

`17.3` GHz
`15.3` GHz
`10.1` GHz
`12.1` GHz

Solution :`f_(1)=f_(s)xx SQRT((1+beta)/(1-beta))`
`=fxxx sqrt((1+(1)/(2))/(1-(1)/(2))) "" [ :. beta=(v)/(c)=(1)/(2)]`
`=fsxxsqrt(((3)/(2))/((1)/2))`
`=10 xx sqrt(3)`
`=10xx1.73`
`=17.3 GHz`


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