1.

An observer moves towards a stationary source of sound with a velocity one-fifth of the velocity of sound. What is the percentage increase in the apparent frequency ?

Answer»

0.2
0.05
0.005
zero

Solution :`(v.)/(v) = ((V+ U_(0))/(V)) = ( V + (1)/(5) V)/(V)= (6)/(5) `
`therefore ` % INCREASE = `(v. -v)/(v )xx 100 = ((6)/(5) - 1) xx 100 = 20%`
correct choice is (a) .


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