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An oil drop of mass m fall through air with a terminal velocity in the presence of upward electric field of intensity `E`. the drop carries a charge `+q`. `R` is the viscous drag force and `f` is the buoyancy force . Them for the motion of the drop.A. there is a net force directed upwardB. there is a net force directed downwardC. `mg=Eq+F+R`D. `mg+Eq=F+R` |
Answer» Correct Answer - C | |