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An oil-immersion objectives of a microscope uses oil of refractive index 1.414. The wavelength of illuminating light is 4850 Å and the semivertical angle is 45^(@). Find the limit of resolution and the resolving power of the microscope. |
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Answer» Solution :Data: `n=1.414, lambda=4.85 xx 10^(-7)m, i_("max") = 45^(@)` The limit of resolution, `d_("MIN") = lambda/(2nsin i_("max")) = (4.85 xx 10^(-7))/(2(1.414) sin45^(@))` LTBGT `=(4.85 xx 10^(-7))/(2(1.414)1/sqrt(2)) = (4.85 xx 10^(-7))/2` `=2.425 xx 10^(-7)`m The resolving power of the microscope, `=1/(d_("min")) = 1/(2.425 xx 10^(-7)) = 4.124 xx 10^(6) m^(-1)` |
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