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An open pipe in 2nd harmonic is in resonance with frequency/. Now one end of the tube is closed and frequency is increased to f, such that the resonance again occurs in nth harmonic, then find n and the relationbetween f_(1),f_(2) |
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Answer» SOLUTION :In CASE `-lambda=l:.f_(1)=(V)/(lambda)=(v)/(l)` In case `(2), lambda=(4l)/(n) :. f_(2)=(v)/(lambda)=(nv)/(4l)` Here n is a odd number `f_(2)=(n)/(4)f_(1)` for FIRST resonance `n=5, f_(2)=(5)/(4) f_(1)` and since `f_(2) GT f_(1)`. |
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