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An open pipe is suddenly closed at one end with the result that the frequency of third harmonic of the closed pipe is found to be higher by `100 Hz` then the fundamental frequency of the open pipe. The fundamental frequency of the open pipe isA. 200 HzB. 300 HzC. 240 HzD. 480 Hz |
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Answer» Correct Answer - A `f_(1)lamda_(1)=v` `f_(1)((4L)/(3))=vrArrf_(1)=(3v)/(4L),f_(2)(2L)=vrArrf_(2)=(v)/(2L)` Given that `f_(1)-f_(2)=100` `rArr (3v)/(2L)-(v)/(2L)=100 rArr(v)/(2L)=200Hz` |
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