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An open vessel containing air is heated form `300 K` to `400 K`. The fraction of air originally present which goes out of it is at `400 K`A. `3//4`B. `1//4`C. `2//3`D. `1//8` |
Answer» One heating the gas in open vessel AT `300 K , P_(1) V_(1) = n_(1) R 300` At `400 K, P_(1) V_(1) =n_(2) R 400` `(n_(1))/(n_(2)) = (400)/(300)` `n_(2) = (3)/(4) n_(1)` Thus `(1)/(4) n_(1)` gas is given out . |
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