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An optical instrument used for angular magnification has a 25 D objective and a 20 D eyepiece. The tube length is 25 cm when the eye is least strained. a. Whether it is a microsciAn optical instrument used for angular magnification has a 25 D objective and a 20 D eyepiece. The tube length is 25 cm when the eye is least strained.e or a telescope? b. What is the angulasr magnificant produced? |
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Answer» `f_(upsilon) = (1)/(25D) = 0.04m = 4 cm,` `f_e = (1)/(25D) = 0.05m = 5 cm.` Tube, length = 25 cm, `upsilon_e = 25 cm.` `:. (1)/(upsilon_0) - (1)/(u_e) = (1)/(f_e)` `-(1)/(25) - (1)/(u_e) = (1)/(5)` `RARR- (1)/(u_e) = (1)/(5) + (1)/(25) = (5+1)/(25) = (6)/(25)` `rArr u_e = - (25)/(6)cm` `:. upsilon_0 = 25 - (25)/(6)` `=25xx (5)/(6) = 20.84cm.` `Again, `(1)/(upsilon_0) - (1)/(u_0) = (1)/(f_0)` `(1)/(20.83) - (1)/(u_0)= (1)/(4)` `rArr - (1)/(40) = (1)/(4) = (1)/(20.84)` `=(5.21 -1)/(20.84) = (4.21)/(20.84)` `rArr - (upsilon_0)/(f_0) = 4.21` So, required MAGNIFICATION (m) `= (upsilon_0)/(u_0) ((D)/(f_e)) = 4.21 xx (25)/(5) = 21.` |
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