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AN ORE CONTAINE 12 %COPPER .HOW MANY KG OF THE ORE ARE REQUIRED TO GET 69KG OF COPPER

Answer» <p>Let the total quantity of the ore be 'x' kgSo, 12 % of that ore is copper.</p><p>(x*12)/100 = 6912x/100 = 693x/25 = 693x = 69*253x = 1725x = 1725/3x = 575 kg</p><p>So, 575 kg ore is required to get 69 kg of copper.</p>


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