1.

An organic compound containes `C=74.0%, H=8.65%` and `N=17.3%`. Its empirical formul aisA. `C_(5)H_(8)N`B. `C_(10)H_(12)N`C. `C_(5)H_(7)N`D. `C_(10)H_(14)N`

Answer» Correct Answer - C
`"Element No. of Mol es Simple Ration"`
`C=74" "74//12=6.1" "6.1//1.2=5.08 ` or `5`
`H=8.65" "8.65//1=8.65" "8.6//1.5=7.16` or `7`
`N=1.73" "1.3//14=1.2" "1.2//1.2=1` or `1`
Therefore Empirical formula `=C_(5)H_(7)N.`


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