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An organic compound contains `C,H` and `O` in the proportion of `6:1:8` by weight, respectively. Its vapour density is 30. Its molecular formula will beA. `C_(2)H_(4)O_(2)`B. `CH4O`C. `CH_(2)O`D. `C_(3)HO` |
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Answer» Correct Answer - a `"Element No. of moles Simple ratio"` `C" "6" "6//12=0.5=1" "1` `H" "1" "1//1=1=2" "2` `O" "8" "8//16=0.5=1" "1` Thus, Empirical formula `=CH_(2)O` Empiricial formula mass `=30` Mol. Mass `2xxVD=2xx30=60` `n=(60)/(30)=2` Mol. formula`=(CH_(2)O)_(2)=C_(2)H_(4)O_(2).` |
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