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An organic compound on analysis was found tocontain 0.032% of Sulphur by mass. Themolecular mass of the compound, if its onemolecule contains two sulphur atoms, is(A) 100000 u(C) 20000u(B) 10000 u(D) 200000 u |
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Answer» Let the molecular mass of compound be 'X'. Atomic mass of sulphur- 32gatomic mass of 2 sulphur atoms= (32*2)g since 0.032 % sulphur is present in the given compound, percentage of sulphur * total molecular weight of compound = weight of sulphur in compound.0.032 % of X = 32*2 (0.032 / 100) * X = 64 X = (64 * 100)/ 0.032X = 2 * 10^5 g The molecular weight of the 200000 u (D) is correct option |
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