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An oscilllator of frequency 680 Hz drives two speakers. The speakers are fixed on a vertical pole at a distance 3m from each other as shown in the fig. A person whose height is almost the same as that of the lower speaker walks towards the lower speaker in a direction perpendicular to the pole. Assuming that these is no reflection of sound from the ground and speed of sound is v = 340 m/s. At some instant, when the person is.at a distance 4m from the pole, the wave function (at the person.s location) that describes the waves coming from the lower speaker is y=A cos(kx - omegat),where A is the amplitude omega = 2piv with v = 680 Hz (given) and k=(2pi)/lambda wave function (at the person.s) location) that described waves coming from the upper speaker can be expressed as |
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Answer» `y=Acos(KX - omegat +PI)` |
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