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An unbiased die is thrown. What is probability of getting : (i) An even number (ii) An odd number (iii) A multiple of 3 (iv) a number 3 or 4 (v) an even number and multiple of 3 (vi) a number between 3 and 6 (vii) A number greater than 3 (viii) A number less than 4 |
Answer» When a die is thrown, all possible outcomes are 1,2,3,4,5,6. Total number of possible outcomes = 6. (I) Let `E_(1)` be the event of getting a 3. Then, the number of favourable outcomes = 1. `:. " P(getting a 3) " = P(E_(1)) = 1/6.` (ii) Let `E_(2)` be the event of getting a 5. Then, the number of favourable outcomes = 1. `:. " P(getting a 5)" P(E_(2)) = 1/6.` (iii) Let `E_(3))` be the event of getting an odd number. Then, the favourable outcomes are 1, 3, 5. Number of favourable outcomes = 3. `:. ` P(getting an old number ) ` =P(E_(3)) = 3/6 = 1/2.` (iv) Let `E_(4)` be the event of getting a number greater than 4. Then, the favourable outcomes are 5, 6. Number of favourable outcomes = 2. `:. ` P(getting a number greater than 4) `P(E_(4)) = 2/6 = 1/3.` |
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