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An Unbiased Die Is Tossed.find The Probability Of Getting A Multiple Of 3?

Answer»

<P>Here S = {1,2,3,4,5,6}

Let E be the event of getting the MULTIPLE of 3

Then, E = {3,6}

P(E) = n(E)/n(S) = 2/6 = 1/3.

Here S = {1,2,3,4,5,6}

Let E be the event of getting the multiple of 3

Then, E = {3,6}

P(E) = n(E)/n(S) = 2/6 = 1/3.


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