In A Bag, There Are 8 Red, 7 Blue And 6 Green Flowers. One Of The Flo

1.	In A Bag, There Are 8 Red, 7 Blue And 6 Green Flowers. One Of The Flower Is Picked Up Randomly. What Is The Probability That It Is Neither Red Nor Green?
Answer» TOTAL number of flowers = (8+7+6) = 21. Let E = event that the flower drawn is neither red nor GREEN. = event TAHT the flower drawn is blue. --> n(E)= 7 --> P(E)= 7/21=1/3. Total number of flowers = (8+7+6) = 21. Let E = event that the flower drawn is neither red nor green. = event taht the flower drawn is blue. --> n(E)= 7 --> P(E)= 7/21=1/3.

In A Bag, There Are 8 Red, 7 Blue And 6 Green Flowers. One Of The Flower Is Picked Up Randomly. What Is The Probability That It Is Neither Red Nor Green?

Answer»

TOTAL number of flowers = (8+7+6) = 21.

Let E = event that the flower drawn is neither red nor GREEN.

= event TAHT the flower drawn is blue.

--> n(E)= 7

--> P(E)= 7/21=1/3.

Total number of flowers = (8+7+6) = 21.

Let E = event that the flower drawn is neither red nor green.

= event taht the flower drawn is blue.

--> n(E)= 7

--> P(E)= 7/21=1/3.