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An unsymmetrical double convex thin lens forms the image of a point object on its axis will the position of the image change if the lens is reversed ? |
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Answer» Solution :`rArr` ACCORDING to formula, `(1)/(f) = ((n_2 - n_1)/(n_1))(1/(R_1) -1/(R_2))` `therefore 1/V -1/u = ((n_2 - n_1)/(n_1))(1/(R_1) - 1/(R_2))` Here even after inverting the LENS (UPSIDE down) values of `u,n_1,n_2` and `(1/(R_1) - 1/(R_2))` remain unchanged. Hence value of v (image distance) will remain same. It means that position of image will unchanged. |
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