1.

An urn contains 5 white and 8 black balls. two successive drawing of 3 balls at a time are made such that balls drawn in first draw are not replaced before the second draw. Find the probability that the first draw gives 3 white balls and second draw gives 3 black balls.

Answer» Correct Answer - `7/429`
Required probability `={(.^(5)C_(3))/(.^(13)C_(3))xx(.^(8)C_(3))/(.^(10)C_(3))}=((5xx4xx3)/(13xx12xx11)xx(8xx7xx6)/(10xx9xx8))`


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