An urn contains 9 red, 7 white, and 4 black balls. A ball is drawn at

1.	An urn contains 9 red, 7 white, and 4 black balls. A ball is drawn at random. Find the probability that the ball is drawn is red
Answer» We know that Probability of occurrence of an event = \(\frac{Total\,no.of\,Desired\,outcomes}{Total\,no.of\,outcomes}\) By permutation and combination, total no. of ways to pick r objects from given n objects isⁿC_r Now, total no. of ways to pick a ball from 20 balls is ²⁰c₁ = 20 Our desired output is to pick a red ball. So, no. of ways to pick a red ball from 9 red balls (because the red ball can be picked from only red balls) is ⁹c₁ = 9 Therefore, the probability of picking a red ball = \(\frac{9}{20}\) Conclusion: Probability of picking a red ball from 9 red, 7 white and 4 black balls is \(\frac{9}{20}\)

An urn contains 9 red, 7 white, and 4 black balls. A ball is drawn at random. Find the probability that the ball is drawn is red

Answer»

We know that

Probability of occurrence of an event

= \(\frac{Total\,no.of\,Desired\,outcomes}{Total\,no.of\,outcomes}\)

By permutation and combination, total no. of ways to pick r objects from given n objects isⁿC_r

Now, total no. of ways to pick a ball from 20 balls is ²⁰c₁ = 20

Our desired output is to pick a red ball. So, no. of ways to pick a red ball from 9 red balls (because the red ball can be picked from only red balls) is ⁹c₁ = 9

Therefore, the probability of picking a red ball = \(\frac{9}{20}\)

Conclusion: Probability of picking a red ball from 9 red,

7 white and 4 black balls is \(\frac{9}{20}\)

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