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An X-ray photon is found to have its wavelength doubled on being scattered through 90^(@). Find the energy of the incident photon: |
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Answer» `8.1xx10^(-14)J` `Delta lambda=(h)/(m_(0)c)(1-cos phi)` when `theta=90^(@), Delta lambda= lambda` (wavelength is doubled) Thus `lambda=(h)/(m_(0)c)=0*024Å` Energy `hv=(hc)/(lambda)=(hc)/(h//m_(0)c)=m_(0)c^(2)` `=(9*0xx10^(-31)xxkgxx3*0xx10^(8) m//"SEC")^(2)` `=8*1xx10^(-14)J` |
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