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An X-ray tube, operated at a potential difference of 40 kV, produce heat at the rate of 720 W.Assuming 0.5% of the energy of incident electrons is converted into X-rays , calculate (i)The number of electron per second striking the target (ii)The velocity of the incident electrons . |
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Answer» Correct Answer - (i) `1.1 xx 10^(17)` (ii) `1.2 xx 10^(8) m//s` (i) Operating voltage `=40 kV, 0.5 %` energy for x ray `:. 99.5/100xxnxxexxV=720` `n=(720)/(1.6xx10^(-14)xx0.995xx40xx10^(3))=1.1xx10^(17)` (ii) Velocity of incident `e^(-)implies 1/2 mv_(e)^(2)=eV` `v_(e)=sqrt((2eV)/m)=sqrt((2xx1.6xx10^(19)xx40xx10^(3))/(9.1xx10^(-31)))` `=1.2xx10^(8) m//s` |
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