InterviewSolution
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InterviewSolution
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An X-ray tube operates at `20k V`. Find the maximum speed of the electron strinking the anode , given the charge of electron is `1.6 xx 10^(-19)` coulomb and mass of electron is `9 xx 10^(-31) kg`. |
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Answer» When an electron of charge `e` is accelerated through a potential different `V`, it acquired energy `e V`. If `m` be the mass of the electron and `v_(max)` the maximum speed of electron , then `(1)/(2) m v_(max)^(2) = e V` or `v_(max) = sqrt(((2 e V)/(m)))` Subsitituting the given value , we get `v_(max) = sqrt(((2 xx (1.6 xx 10^(-19)) xx 20.000)/(9 xx 10^(-31))))` `= 8.4 xx 10^(7) ms^(-1)` |
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