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An X - ray tube produces a continous spectrum of radiation with its short wavelength end at 0.45 `Å` . What is the maximum energy of a photon in the radiation? |
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Answer» Given , ` lambda = 0.45 Å = 0.45 xx 10^(-10) m, E = (hc)/lambda = (6.63 xx 10^(-34) xx 3 xx 10^(8))/(0.45 xx 10^(-10) xx 1.6xx 10^(-19) ) eV ` ` :. E = 27.6 xx 10^(3) eV = 27.6 KeV` |
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