InterviewSolution
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InterviewSolution
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Analyze the generalized rate data: `RX + M^(ɵ) rarr` Product `|{:("Experiment",[RX] "Substrate",[M^(ɵ)] "Attaking species","Rate"),(I,0.10 M,0.10 M,1.2 xx 10^(-4)),(II,0.20 M,0.10 M,2.4 xx 10^(-4)),(III,0.10 M,0.20 M,2.4 xx 10^(-4)),(IV,0.20 M,0.20 M,4.8 xx 10^(-4)):}|` The value of rate constant for the give experiment data isA. `1.2 xx 10^(-2)`B. `1.2 xx 10^(-4)`C. `1.2 xx 10^(-3)`D. `2.4 xx 10^(-3)` |
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Answer» Correct Answer - A form experimetn I and II, when the concentration of `[RX]` becomes double, rate becomes double, so order w.r.t. `(RX) = 1`. ismilarly, form experiments II and IV, when the concentration of `M^(ɵ)` is doubled, rate also is doubled. So order w.r.t `[M^(ɵ)] = 1`. Hence, rate `= k[RX][M^(ɵ)]` ...(i) So overall second order reaction. form Eq. (i), `1.2 xx 10^(-4) = k[0.1][0.1]` `:. k = 1.2 xx 10^(-2)` |
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