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Angle B of triangle ABC is an acute angle and AD perpendicular BC prove that AC2 =AB2+BC2-2BC-BD2 |
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Answer» Answer: ANSWER Since triangles ABd and ACD are right angled at D. Therefore, AB =AD 2 +BD 2 ......................1 And, AC 2 =AD 2 +CD 2 ........................2 Subtracting 2 from 1 we get AB 2 −AC 2 =BD 2 −CD 2 |
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