1.

Angle of deviation (delta) for a prism (refractive index mu and supposing prism angle A to be small) is given by:

Answer»

`(DELTA)=((mu-1)/(mu+1))A`
`(delta)=(mu-1)A`
`(delta)=(SIN( A+delta)/2)/Sin(A/2)`
`(delta)=(mu+1)A`

ANSWER :B


Discussion

No Comment Found

Related InterviewSolutions