1.

Angular momentum of an electron in an excited hydrogen atom having energy -3.4eV is :

Answer»

`1.7 xx 10^(-34)Js`
`2.1 xx 10^(-34)Js`
`3.9 xx 10^(-34)Js`
`4.1 xx 10^(-35)Js`

Solution :Here, `E_(n)=-R_(H) (ch)/(n^(2))`
`n^(2)=-(R_(H).ch)/(E_(n)) rArr n^(2)=4 rArr n=2`
ALSO, mvr `=(NH)/(2pi)=2.11 xx 10^(-34)Js`


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