1.

Angular width of a central max is 30^(@) when the slits is illuminated by light of wavelength 6000 Å.Then width of the slit will be approx:

Answer»

`12 xx 10^(-6) m`
`12 xx 10^(-7) m`
`12 xx 10^(-8) m`
`12 xx 10^(-9) m`

SOLUTION :Angular WIDTH `theta = 30^(@)`
`therefore sin 30^(@) = (LAMBDA)/(a)`
`therefore a = (lambda)/(sin 30^(@)) = 12000 xx 10^(-10)` m
`= 12 xx 10^(-7)`m.


Discussion

No Comment Found

Related InterviewSolutions