Ans it fast with complete solution

1.	Ans it fast with complete solution
Answer» Step-by-step explanation: Now, (X+ y)3 – (X3 + y3) = (x + y) – (x + y)(X2– xy + y2) [USING identity, a3 + b3 = (a + b)(a2 -ab+ b2)] = (x+ y)[(x+ y)2 -(x2 -xy+ y2)] = (x+ y)(x2+ y2+ 2xy- x2+ xy- y2) [using identity, (a + b)2 = a2 + b2 + 2 ab)] = (x + y) (3xy) Hence, ONE of the factor of given polynomial is 3xy MARK ME AS BRAINLIST

Answer»

Step-by-step explanation:

Now, (X+ y)3 – (X3 + y3) = (x + y) – (x + y)(X2– xy + y2)

[USING identity, a3 + b3 = (a + b)(a2 -ab+ b2)] = (x+ y)[(x+ y)2 -(x2 -xy+ y2)]

= (x+ y)(x2+ y2+ 2xy- x2+ xy- y2)

[using identity, (a + b)2 = a2 + b2 + 2 ab)]

= (x + y) (3xy)

Hence, ONE of the factor of given polynomial is 3xy

MARK ME AS BRAINLIST

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