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Answer fast i am giving 100 credits |
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Answer» Step-by-step EXPLANATION:cosec X=cosec 2x+cosec 4x1/sinx=1/SIN 2x+1/sin 4xsin 2x*sin 4x/sin x=sin 2x+sin 4xSin C+Sin D=2 Sin (C+D/2) Cos(C-D/2)Sin 2x=2 Sinx Cosx2*sinx*COSX*sin 4x/sinx=2 sin (3x) cos (x)2 cosx sin 4x=2 sin(3x) cos(x)cos(x) {sin 4x-sin 3x}=0Sin C-sin D= 2 cos (C+D/2) sin (C-D/2)2 cos(x) {sin(x/2) cos(7x/2)}=0Cosx=0 ==== x=(2n+1)/2Sin(x/2)=0===== x=2n cos(7x/2)=0===== 7x/2=2n+1(/2) x=2/7 (2n+1)(/2)Where n∈Z I hope it is clear...please mark as brainliest and thank if it helps... |
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