Answer itno spamno spamspam answerss will be reportedCorrect answer i

1.	Answer itno spamno spamspam answerss will be reportedCorrect answer i will Follow them
Answer» Answer: let the side AC be HYPOTENUSE of trinagle ∆ ABC let the side BC be base of TRIANGLE of ∆ ABC GIVEN : *side* AC = 17 *and* *side* BC = 10.5 *Applying* *Pythagoras* *theorem* *Hyp²* = *base²* + *height²* (17)² = (10.5)² + (*HEIGHT)² 289 = 110.25 + height²* *height²* = 289 - 110.25 = 178.75 *taking* √ *both* *side* *height²* = √178.75 *height* = 13.36 I *think* *this* is *the* *answer.* if it is *not* *perfect* *for* *you* *then* *can* *report* *me.*

Answer itno spamno spamspam answerss will be reportedCorrect answer i will Follow them

Answer»

Answer:

let the side AC be HYPOTENUSE of trinagle ∆ ABC

let the side BC be base of TRIANGLE of ∆ ABC

GIVEN : side AC = 17 and side BC = 10.5

Applying Pythagoras theorem

Hyp² = base² + height²

(17)² = (10.5)² + (HEIGHT)²

289 = 110.25 + height²

height² = 289 - 110.25

= 178.75

taking √ both side

height² = √178.75

height = 13.36

I think this is the answer. if it is not perfect for you then can report me.