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Answer my two questions |
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Answer» step solution 1.question. let FIRST ANGLE = xas given SECOND angle is 4/5 of first angleso = 4/5 off= 4x/5A complementary angle measure =90 degree. 90 degree = 4x/5+x/1=9x/590*5=9x450= 9x450/9=x50degree = x4/5ofx= 4/5*50=40degree 2.question.let first supplement = xsecond = x+40a supplementary angle measure = 180 degree180=x+x+402x+40=1802x =180-40x=140/2=70degree as given second angle is first angle + 40so second angle = 70+40 =110degree110+70=180I have solved and note this question in so much TIME can you PLEASE mark me as brainliest |
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