Saved Bookmarks
| 1. |
Answer the above. please don't spam okay. |
|
Answer» AOB=90 o Join OC OC⊥AB(Tangent at any pt of circle is far to RADIUS)∠ACO=∠BCO=90 o In ΔAOP & ΔAOCOP=OCAP=AC (LENGTH of drawn from external point to circle are equal)⇒ΔAOP≅ΔAOCIn ΔBOC & ΔBOQwith same argumentΔBOC≅ΔBOQ∠BOC=∠BOQ (CPCT)for LINE PQ∠AOP+∠AOC+∠BOC+∠BOQ=1802∠AOC=2∠BOC=180⇒∠AOC+∠BOC=90⇒∠AOB=90hope it helps dearif found helpful mark it as brainiliest and follow PL |
|