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Answer the following:1. The point (5,-3) lies in the quadrant2. The point whose ordinate is 4 and which lies on y-axis is3. The perpendicular distance of the point (4,3) from x-axis is4. Point of intersection of the axes is called5. The graph of x = a is a line parallel to axis.6. Find the value of k, if x = 1, y = 1 is the solution of the equation3x - 4y = k.7. The cost of a table is twice the cost of a chai,,"write a linearequation in two variables to represent this statement.8. How many solutions are there for the linear equation 2x - 5y = 7.9. How can we write the equation x = 7 in two variables,10. Is (1,2) a solution of 2x + 3y = 8 ? Justify11. Find three solutions of the equations 2x + 3y = 612. In which quadrant or on which axis the following points lie :i. (2,7) ii. (-6,3) iii.(9,0) iv. (0,-4)13. Give the geometrical representation of 2% - 6 = 0 as an equation :6) in one variable (ii) in two variables14. Plot the points A (4,0), B (4,4), C(0,4) in the Cartesian plane. Name the figure soobtained by joining the points AB, BC and AC.15. Write the following equations in the form ax + by +c= 0 and indicate the values of a, b and cin each case : (i)-4 = V3y (ii) 2x = 4y16. Draw the linear graph for 2x +y = 6.17. The auto rickshaw fare in a city is charged Rs 10 for the first km and at Rs 4 per km forsubsequent distance covered. Write the linear equation to express the above statement.Draw the graph of the linear equation.18. If (2,0) is a solution of the linear equation 2x +3y = k, then find the value of k.19. Check whether ( 4 , 1) is a solution of the equation 2x - y = 520. Write the abscissa and ordinate for the following points:i) B(4,3) (ii) K (-6,-5)someone please help me find answered for all these questions |
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Answer» Answer: 1.the POINT (5,-3) lies in puadrant 4 2.the point which ordinate is 4 and lies in y-axis is (0,4) 3.the perpendicular distance of the point (4,3)from x-axis is 4 unit 4.point of intersection of the axis is called origin 5.the graph of x=ais a lineparallel to y-axis 6.(x=1) (y=1) by putting the value of x and y in the expression 3x - 4y = k =>3×1 - 4×1=k =>3 - 4 = -1 = k hence k = -1 7.let the coast of the table be x so ATQ y = 2x =>2x-y=0 this is required linear equation in two variable 8.2x -5y = 7 for this equation their are million of solution 9.we can write this equation like 2x-x=7.-9x+10x=7 and etc 10.here x = 1 and y =2 the by putting the value of x and y in expression =2x+3y =2×1+3×2 =2+6 =8 so we can proofe or we can say that (1,2) is a solution for 2x+3y=8 11.2x+3y=6 (x=1) =>2×1+3y=6 =>2+3y=6 =>3y=6-2 =>3y=4 =>y=4/3 so FIRST solution is (1,4/3) (x=2) 2×2+3y=6 4+3y=6 3y=6-4 3y=2 y=2/3 so second solution is (2,2/3) (x=3) 2×3+3y=6 6+3y=6 3y=6-6 y=0/3 y=0 so third solution is (3,0) 12.i)1st ii)2nd iii)1st iv)4th |
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