answer this please

1.	answer this please
Answer» Here, from right to LEFT, $\sqrt{x + 2}$ is repeating 3 TIMES (or it happens ENDLESSLY also!). So in such problems, as we do from right to left, same answer is repeating as each $\sqrt{x + 2}$ is being PASSED through. ∴ $\sqrt{x + 2\sqrt{x + 2\sqrt{x + 2\sqrt{3x}}}} = \sqrt{x + 2\sqrt{x + 2\sqrt{3x}}} = \sqrt{x + 2\sqrt{3x}}$ $= \sqrt{3x} = x$ $3x = x^2 \\ = 3 * x = x * x$ ∴ $x = 3$ . Let's CHECK. $\sqrt{3 + 2\sqrt{3 + 2\sqrt{3 + 2\sqrt{3 * 3}}}} \\ = \sqrt{3 + 2\sqrt{3 + 2\sqrt{3 + 2 * 3}}} \\ = \sqrt{3 + 2\sqrt{3 + 2\sqrt{3 + 6}}} \\ = \sqrt{3 + 2\sqrt{3 + 2\sqrt{9}}} \\ = \sqrt{3 + 2\sqrt{3 + 2 * 3}} \\ = \sqrt{3 + 2\sqrt{3 + 6}} \\ = \sqrt{3 + 2\sqrt{9}} \\ = \sqrt{3 + 2 * 3} \\ = \sqrt{3 + 6} \\ = \sqrt{9} \\ = 3$ If $\sqrt{x + (n - 1)\sqrt{x + (n - 1)\sqrt{x + (n - 1).........\sqrt{x + (n - 1)\sqrt{nx}}}}} = x$ , then $x = n$ . Hope this will be helpful.