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Answer with solutiondon't spam |
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Answer» BEC+∠DEC=180 ∘ (COMPLIMENTARY ANGLES) 130 ∘ +∠DEC=180 ∘ ∠DEC=50 ∘ In ΔDEC - ∠DEC+∠ECD+∠CDE=180 ∘ ∠CDE=110 ∘ by THEOREM of CIRCLES -∠BAC=∠CDE∴∠BAC=110 ∘ |
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