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96% of 20 KG is water, i.e.,
20 \times  \frac{96}{100}  = <klux>19</klux>.<klux>2</klux> \:  \: kg \:  \: ..............(1)
is water initially.

Finally, the amount of water,
20 \times  \frac{95}{100}  = 19 \:  \: kg \:  \: .................(2)
So amount of weight reduced =
EQUATION (1) – equation (2)
= 19.2 – 19 kg
So amount of weight reduced = 0.2kg



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