1.

Aparallel beam of monochromatic light of wavelength 4000 Å is incident normally on a single narrow slit of width 0.0008 mm. The light is focused by a a convex lens on a screen placed in focal plane. The first minimum will be formed for the angle of diffraction equal to

Answer»

`0^(@)`
`15^(@)`
`30^(@)`
`50^(@)`

Solution :For FIRST minima
`d sin THETA= n lambda=1 lambda [ :. N=1]`
`sin theta=(lambda)/(d)`
`=(5000xx10^(-10))/(0.001xx10^(-3))=0.5`
`:. theta=30^(@)`


Discussion

No Comment Found

Related InterviewSolutions