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Aperture of lens of a camera is f and its exposure time is (1)/(60) s. If aperture becomes 1.4 f, then what will be the exposure time ? |
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Answer» `(1)/(42)` s `therefore ((t_2)/(t_1))=((f_2)/(f_1))^2` `therefore t_2=t_1xx((f_2)/(f_1))^2` `=(1)/(60)xx((1.4f)/(f))^2` `=((1.4)^2)/(60)=0.03266` `therefore t_2=(1)/(31)` s |
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