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Apply Gauss's theorem to find an expression for the electric field intensity at a point due to a point charge. |
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Answer» Solution :let us find electric FIELD intensity due to a POINT charge q at a point P at distance r. draw a gaussian sphere of a RADIUS r passing through the point of observation as SHOWN in the fig. From Gauss.s theorem, `ointvec(E).dvec(S)=(q)/(epsi_(0))` or `ointEdScos0^(@)=(q)/(epsi_(0))`  or `EointdS=(q)/(epsi_(0))``[becausecos0^(@)=1]` or `E.4pir^(2)=(q)/(epsi_(0))` or `E=(q)/(4pir^(2)epsi_(0))` or `E=(1)/(4piepsi_(0))(q)/(r^(2))`. |
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