1.

Aradioactive isotope has t_(1//2) of 10 days. If today 125 g of it is left, what was its weight 40 days earlier ?

Answer»

2g
600g
1g
`1.5g`

Solution :`N=N_(0)((1)/(2))^(n)n=(40)/(10)=4`
`(125)/(1000)=N_(0)((1)/(2))^(4),N_(0)=(125)/(1000)xx2xx2xx2xx2=2g`


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