InterviewSolution
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InterviewSolution
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Area bounded between the curve `x^(2)=y` and the line y = 4x isA. `(32)/(3)` sq. unitB. `(1)/(3)` sq unitC. `(8)/(3)` sq unitD. `(16)/(3)` sq unit |
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Answer» Correct Answer - A Given curves are ` x^(2)=y and y=4x` Intersection point are ` (0,0)` and (4,16) `:.` Required are `=int_(0)^(4) (4x-x^(2)) dx` `=[(4x^(2))/(2)-(x^(3))/(3)]_(0)^(4)` `=[32-(64)/(3)]` `=(32)/(3)` sq unit |
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