1.

Area of a surface is 1256 m^(2). If 25 Js^(-1) radiant energy is incident on it at each second and absorbed completely, then findE_(rms)

Answer»

SOLUTION :`I=E_(0)CE_(rms)^(2)`
`E_(rms)^(2)=(I)/(in_(0)C)=(0.02)/(8.85xx10^(-12)xx3xx10^(8))`
= 7.5329
`THEREFORE E_(rms)=SQRT(7.5329)=2.7446~~2.74 Vm^(-1)`


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