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Area of a surface is 1256 m^(2). If 25 Js^(-1) radiant energy is incident on it at each second and absorbed completely, then findE_(rms) |
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Answer» SOLUTION :`I=E_(0)CE_(rms)^(2)` `E_(rms)^(2)=(I)/(in_(0)C)=(0.02)/(8.85xx10^(-12)xx3xx10^(8))` = 7.5329 `THEREFORE E_(rms)=SQRT(7.5329)=2.7446~~2.74 Vm^(-1)` |
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