1.

Area of a surface is 1256 m^(2). If 25 Js^(-1) radiant energy is incident on it at each second and absorbed completely, then findMagnitude of energy density

Answer»

SOLUTION :`rho=(I)/(C )=(0.02)/(3XX10^(-8))=0.00666xx10^(8)`
`~~6.67xx10^(11)JM^(-3)`


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