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Arrange the following steps of construction while constructing a triangle of scale AB = 2.3 cm, BC = 5 cm and AC = 2.9 cm such that each of its sides is 2/3 rd of the corresponding side of the ΔABC.Steps of ConstructionStep I : On BE, cut off 3 equal parts making B1, B2 and B3.Step ll : Now, draw C'A' parallel to CA. Then, ΔA'BC' is the required Δ whose sides are 2/3rd of the corresponding sides of the ΔABC.Step III : From point B draw an arc of f.3 cm and from point C draw an arc of 2.9 cm cutting each other at point A.Step IV : Take BC = 5 cm.Step V : Join B3C and from B, draw B2C' parallel to B3C, such that BC' is 2/3 of BC.Step VI: On B make an acute ∠CBE downwards.Step VII : Join AB and AC. Then ABC is the required triangle.(A) IV, III, VII, I , VI, V, II(B) IV, V, I, VI, III, VII, II(C) IV, III, VII, VI, I, V, II(D) IV, VII, III, VI, V, I, II |
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Answer» The correct option is: (C) IV, III, VII, VI, I, V, II Explanation: Correct sequence of steps is IV, III, VII, VI, I, V, II |
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