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Arrhenius studies the effect of temperature on the rate of a reaction and postulted that rate constant varies with temperature exponentially as `k=Ae^(E_(a)//RT)` . Thuis method is generally used for finding the activation energy of a reaction. Keeping temperature constant, the effect of catalyst on the activation energy has also been studied. If the rate of reaction doubles for `10^(@)C` rise of temperature form 290K to 300K, the activation energy of the reaction will be approximately :A. 40 Kcal `mol^(-1)`B. 12 Kcal `mol^(-1)`C. 60 Kcal `mol^(-1)`D. 70 Kcal `mol^(-1)` |
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Answer» Correct Answer - B |
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