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Size of nucleus was obtained by the equation `r=R_(0)A^(1//3)` , Where r is the radius of nucleus of mass no A. and `R_(0)` is a constant whose valie is equal to `1.5xx10^(-15)` metre. (Given : 1 amu = `1.66xx10^(-24)g`) What is the density of a nucleus of mass number A ?A. `(4)/(3)pi(1.5xx10^(-15))^(3)` AB. `1.17xx10^(17)kg//cm^(3)`C. `1.17xx10^(-17)kg//m^(3)`D. none of these

Answer» Correct Answer - B


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