1.

As a rejult of change in the magnetic flux linked to the closed loop shown in the figure, an emf V volt is induced in the loop. The work done (joules) in taking a charge Q coulomb once along the loop is

Answer»

`QV`
`zero`
`2QV`
`(QV)/(2)`

Solution :Induced emf WORK done in TAKING a CHARGE
`(Q "once along the LOOP")/("charge"Q)`
i.e., is `V=(W)/(Q)`
`impliesW=VQ`


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